(x+4)(2x^2-11x-5)=0

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Solution for (x+4)(2x^2-11x-5)=0 equation:


Simplifying
(x + 4)(2x2 + -11x + -5) = 0

Reorder the terms:
(4 + x)(2x2 + -11x + -5) = 0

Reorder the terms:
(4 + x)(-5 + -11x + 2x2) = 0

Multiply (4 + x) * (-5 + -11x + 2x2)
(4(-5 + -11x + 2x2) + x(-5 + -11x + 2x2)) = 0
((-5 * 4 + -11x * 4 + 2x2 * 4) + x(-5 + -11x + 2x2)) = 0
((-20 + -44x + 8x2) + x(-5 + -11x + 2x2)) = 0
(-20 + -44x + 8x2 + (-5 * x + -11x * x + 2x2 * x)) = 0
(-20 + -44x + 8x2 + (-5x + -11x2 + 2x3)) = 0

Reorder the terms:
(-20 + -44x + -5x + 8x2 + -11x2 + 2x3) = 0

Combine like terms: -44x + -5x = -49x
(-20 + -49x + 8x2 + -11x2 + 2x3) = 0

Combine like terms: 8x2 + -11x2 = -3x2
(-20 + -49x + -3x2 + 2x3) = 0

Solving
-20 + -49x + -3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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